Activity for MissMulanâ€
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Edit | Post #283259 | Initial revision | — | over 2 years ago |
| Answer | — |
A: Signal modeling as only digital, only analogue, or as both If a signal has a analog component then it analog regardless of if it has a digital component. (more) |
— | over 2 years ago |
| Comment | Post #283258 |
I don't think this has anything to do with physics. (more) |
— | over 2 years ago |
| Edit | Post #283251 |
Post edited: |
— | over 2 years ago |
| Edit | Post #283251 |
Post edited: |
— | over 2 years ago |
| Comment | Post #283251 |
And i have something else in my mind lets just say the initial acceleration is 0. (more) |
— | over 2 years ago |
| Edit | Post #283251 |
Post edited: |
— | over 2 years ago |
| Comment | Post #283251 |
HDE 226868 you are correct i will edit (more) |
— | over 2 years ago |
| Edit | Post #283251 |
Post edited: |
— | over 2 years ago |
| Edit | Post #283251 | Initial revision | — | over 2 years ago |
| Question | — |
Find jerk of time varying force This gravitational field we move inside has some distance L after which it becomes 0.Before L it is just like any gravitational field. Suppose we move inside that gravitational field.The acceleration we experience depends on the distance from the planet. $$a\sim\frac{1}{r^2}$$ At t=to we enter t... (more) |
— | over 2 years ago |
| Edit | Post #283009 | Initial revision | — | almost 3 years ago |
| Question | — |
Motion of charged particle inside a magnetic field We have place a charged particle of 2C with mass 2kg, 1mm above a current-carrying wire of 1A.The charged particle has an initial velocity of 100m/s The magnetic field of the wire for simplicity will exist as long as we are only over the wire. How can we find the equation of motion of the p... (more) |
— | almost 3 years ago |
| Edit | Post #282727 | Initial revision | — | almost 3 years ago |
| Question | — |
Magnetic charges to solve interaction between 2 magnetic dipoles Suppose we have an electric dipole of charge Q+ and Q-.The charges of the dipole are fixed (they cant move closer to each other than they already are).If we place a test particle at some distance r from the electric dipole it is pretty straight forward we calculate the electric force between each of ... (more) |
— | almost 3 years ago |
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