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I have a circuit like this. And, I want to calculate resistance from here. I was following these steps. I was calculating resistance for left side circuit. $$R_1=\frac{2 × 2}{2+2+4}=0.5\Omega$$...
#3: Post edited
- [![enter image description here][1]][1]
I have a circuit like this. I was following these [steps](https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/).- I was calculating resistance for left side circuit.
- $$R_1=\frac{2 × 2}{2+2+4}=0.5\Omega$$
- $$R_2=\frac{2 × 4}{2+2+4}=1\Omega$$
- $$R_3=\frac{2 × 4}{2+2+4}=1\Omega$$
- Then, I took series and parallel circuit. Then, calculated equivalent of resistance.
- $$R_s1=0.5+3=3.5$$
- $$R_s2=1+3=4$$
- $$R_p=(\frac{1}{3.5}+\frac{1}{4})^-1=1.8677$$
- $$Requivalent=1.8677+1=2.8667$$
- I am not sure if it is correct. If it is wrong than how can I proceed?
- [1]: https://i.stack.imgur.com/dbNPL.png
- [![enter image description here][1]][1]
- I have a circuit like this. And, I want to calculate resistance from here. I was following these [steps](https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/).
- I was calculating resistance for left side circuit.
- $$R_1=\frac{2 × 2}{2+2+4}=0.5\Omega$$
- $$R_2=\frac{2 × 4}{2+2+4}=1\Omega$$
- $$R_3=\frac{2 × 4}{2+2+4}=1\Omega$$
- Then, I took series and parallel circuit. Then, calculated equivalent of resistance.
- $$R_s1=0.5+3=3.5$$
- $$R_s2=1+3=4$$
- $$R_p=(\frac{1}{3.5}+\frac{1}{4})^-1=1.8677$$
- $$Requivalent=1.8677+1=2.8667$$
- I am not sure if it is correct. If it is wrong than how can I proceed?
- [1]: https://i.stack.imgur.com/dbNPL.png
#2: Post edited
- [![enter image description here][1]][1]
- I have a circuit like this. I was following these [steps](https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/).
- I was calculating resistance for left side circuit.
- $$R_1=\frac{2 × 2}{2+2+4}=0.5\Omega$$
- $$R_2=\frac{2 × 4}{2+2+4}=1\Omega$$
- $$R_3=\frac{2 × 4}{2+2+4}=1\Omega$$
- Then, I took series and parallel circuit. Then, calculated equivalent of resistance.
- $$R_s1=0.5+3=3.5$$
- $$R_s2=1+3=4$$
- $$R_p=(\frac{1}{3.5}+\frac{1}{4})^-1=1.8677$$
- $$Requivalent=1.8677+1=2.8667$$
I am not sure if it is correct.- [1]: https://i.stack.imgur.com/dbNPL.png
- [![enter image description here][1]][1]
- I have a circuit like this. I was following these [steps](https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/).
- I was calculating resistance for left side circuit.
- $$R_1=\frac{2 × 2}{2+2+4}=0.5\Omega$$
- $$R_2=\frac{2 × 4}{2+2+4}=1\Omega$$
- $$R_3=\frac{2 × 4}{2+2+4}=1\Omega$$
- Then, I took series and parallel circuit. Then, calculated equivalent of resistance.
- $$R_s1=0.5+3=3.5$$
- $$R_s2=1+3=4$$
- $$R_p=(\frac{1}{3.5}+\frac{1}{4})^-1=1.8677$$
- $$Requivalent=1.8677+1=2.8667$$
- I am not sure if it is correct. If it is wrong than how can I proceed?
- [1]: https://i.stack.imgur.com/dbNPL.png
#1: Initial revision
Delta to Wye conversion
[![enter image description here][1]][1]
I have a circuit like this. I was following these [steps](https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/).
I was calculating resistance for left side circuit.
$$R_1=\frac{2 × 2}{2+2+4}=0.5\Omega$$
$$R_2=\frac{2 × 4}{2+2+4}=1\Omega$$
$$R_3=\frac{2 × 4}{2+2+4}=1\Omega$$
Then, I took series and parallel circuit. Then, calculated equivalent of resistance.
$$R_s1=0.5+3=3.5$$
$$R_s2=1+3=4$$
$$R_p=(\frac{1}{3.5}+\frac{1}{4})^-1=1.8677$$
$$Requivalent=1.8677+1=2.8667$$
I am not sure if it is correct.
[1]: https://i.stack.imgur.com/dbNPL.png