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Comments on What does Lagrangian actually represent?

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What does Lagrangian actually represent?

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$L=T-U$ Here, $L$ is Lagrangian. T is kinetic energy. U is potential energy. But, what Lagrangian actually is? I know what Holonomic and non-holonomic is. But, I was thinking what the Lagrangian represent. Like, F represent force applied on some body. To me, Lagrangian is just representing some kind energy. But, what type of energy?

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Lagrangian is no energy. It’s just the Lagrangian. It's perhaps more fundamental than energy in a certain sense. In general, you can think of it as a function that minimizes the action. That's the definition of Lagrangian. ~ said by Golam Ishtiak (You can find him right here also)

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I don't have any opinion on it. Just posted what he told me.

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Lagrangians don't minimize the action (1 comment)
Lagrangians don't minimize the action
Derek Elkins‭ wrote over 2 years ago

The Lagrangian doesn't minimizes the action. The Lagrangian is the integrand of the integral defining the action. The action is a function of trajectories. The trajectories that make the action stationary (not necessarily minimal) are the physically realizable trajectories. The Lagrangian isn't a trajectory so it doesn't even make sense to ask whether it minimizes the action.

Really, it's hard to define "Lagrangian" on its own. Pretty much any function at all can be called a (potentially higher- or lower-order) Lagrangian. You can define an action from it and produce (potentially higher- or lower-order) Euler-Lagrange equations from it. "Lagrangian" is a term that refers to part of a larger system, namely Lagrangian mechanics, in the same way "integrand" refers to a part of a larger expression. You can't classify arbitrary functions into ones that are integrands and ones that aren't.