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# Motion of charged particle inside a magnetic field

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We have place a charged particle of 2C with mass 2kg, 1mm above a current-carrying wire of 1A.The charged particle has an initial velocity of 100m/s

The magnetic field of the wire for simplicity will exist as long as we are only over the wire.

How can we find the equation of motion of the particle? The force acting on it will be changing because it will move away from the wire and the angle between the particle's velocity with the magnetic field will change as well?

I thought to find the time the particle spends inside the magnetic field

$$d = u\times t \implies t = \frac{d}{u} = 5\,\text{s}$$

but in order to integrate with respect to t I have to find how the distance from the wire changes as time passes and the relationship between time and the angle between the velocity and the magnetic field which are pretty hard and i am stuck. How do I continue?

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# Comments on Motion of charged particle inside a magnetic field

What exactly do you mean with “the time the particle spends in the magnetic field”?
celtschk‭ wrote about 1 year ago:

What exactly do you mean with “the time the particle spends in the magnetic field”? Since the magnetic field of the wire is non-zero in the entirety of space (except inside the wire, but the particle won't go there anyway), the time the particle spends inside the field is infinite. Do you have a specific threshold of the field strength in mind (and if so, what is it)?

MissMulan‭ wrote about 1 year ago:

I am assuming for simplicity the B field becomes 0 after the particle reaches the end of the wire.

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