Activity for TripleFaultâ€
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Edit | Post #283937 | Initial revision | — | over 2 years ago |
| Answer | — |
A: Slipping and rotation I know this is a bit late, but if you still haven't figured it out, here goes: Firstly, let the mass per unit area of the disk be $\sigma = \frac{m}{\pi R^2}$. Consider a small element of area $dA$ at a distance $x$ from the center of the disk. The mass of this element is $dm = \sigma dA$. The ... (more) |
— | over 2 years ago |
| Comment | Post #280944 |
@OlinLathrop yeah it does not, what I meant was the mean radius of curvature, which I believe should work fairly well. (more) |
— | about 3 years ago |
| Edit | Post #280944 | Initial revision | — | about 3 years ago |
| Question | — |
Applying Young-Laplace equation on meniscus formed due to rise of liquid on a single plate Let's say we have a single plate with liquid on both sides rising up due to surface tension. The meniscus formed has a radius of curvature $R$. I'm trying to find the excess pressure, i.e, the pressure difference between the exterior and interior of the meniscus. Since there is only one curved ... (more) |
— | about 3 years ago |