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Let w be the price of water that I'll use to dilute. Forget that. Unless you are in extraordinary circumstances, the price of water is so low compared to the vinegar as to be irrelevant. How do ...
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#2: Post edited
by
Mithical
·
2023-08-30T07:43:35Z (about 1 year ago)
I can't tell whether this is trolling or a serious question, since finding the answer only requires seventh grade math. I'll humor it and give a real answer - for now.- <blockquote>Let w be the price of water that I'll use to dilute.</blockquote>
- Forget that. Unless you are in extraordinary circumstances, the price of water is so low compared to the vinegar as to be irrelevant.
- <blockquote>How do I deduce which concentration (of Vinegar) is cheapest to buy?</blockquote>
- Consider the price of only the vinegar portion of each solution you can buy. For example, if 500 ml of 45% solution costs \\$3.00, then the price of just the vinegar part is \$3.00/45% = $6.67 per 500 ml.
- Do this for each of the possibilities, and normalize them all to the same volume. Let's say you normalize all to the cost of 100 ml of actual vinegar. In the example above, the price would \\$1.33 per 100 ml. Repeat for each offering and compare.
- <blockquote>Let w be the price of water that I'll use to dilute.</blockquote>
- Forget that. Unless you are in extraordinary circumstances, the price of water is so low compared to the vinegar as to be irrelevant.
- <blockquote>How do I deduce which concentration (of Vinegar) is cheapest to buy?</blockquote>
- Consider the price of only the vinegar portion of each solution you can buy. For example, if 500 ml of 45% solution costs \\$3.00, then the price of just the vinegar part is \$3.00/45% = $6.67 per 500 ml.
- Do this for each of the possibilities, and normalize them all to the same volume. Let's say you normalize all to the cost of 100 ml of actual vinegar. In the example above, the price would \\$1.33 per 100 ml. Repeat for each offering and compare.
#1: Initial revision
by
Olin Lathrop
·
2023-08-19T22:14:54Z (over 1 year ago)
I can't tell whether this is trolling or a serious question, since finding the answer only requires seventh grade math. I'll humor it and give a real answer - for now. <blockquote>Let w be the price of water that I'll use to dilute.</blockquote> Forget that. Unless you are in extraordinary circumstances, the price of water is so low compared to the vinegar as to be irrelevant. <blockquote>How do I deduce which concentration (of Vinegar) is cheapest to buy?</blockquote> Consider the price of only the vinegar portion of each solution you can buy. For example, if 500 ml of 45% solution costs \\$3.00, then the price of just the vinegar part is \$3.00/45% = $6.67 per 500 ml. Do this for each of the possibilities, and normalize them all to the same volume. Let's say you normalize all to the cost of 100 ml of actual vinegar. In the example above, the price would \\$1.33 per 100 ml. Repeat for each offering and compare.