Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

How are gravitational waves derived?

+0
−0

Gravitational waves can be derived from the non-linear Einstein field equations and since they are by definition waves they must obey the wave equation:

$u_{tt}=c^{2}u_{xx}$ but in General Relativity time and space are not fixed so how are $t$ and $x$ defined for a gravitational wave?

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.
Why should this post be closed?

0 comment threads

1 answer

+2
−0

The typical 'most simple' derivation of the gravitational wave equation (GWE) starts by a perturbation of the 'background metric' $\bar{g}$ to get $g_{\mu\nu} = \bar{g}_{\mu\nu} + h_{\mu\nu}$, where $h$ is the perturbation that will be described by a wave equation.

'Far away' from the source of this perturbation, this derivation then considers the case where there is no (background) matter, gravity etc. to give that the stress-energy-momentum tensor far away from the source is approximated as $T_{\mu\nu} = 0$ and $\bar{g}_{\mu\nu} = \eta_{\mu\nu}$.

We then define $\bar{h}^{\mu\nu} = h^{\mu\nu} - \frac{1}{2}\eta^{\mu\nu}h^\alpha_\alpha$, which in the gauge $\partial_\mu \bar{h}^{\mu\nu} = 0$, gives the wave equation $$\Box\bar{h} = 0.$$

This is the equation of a wave travelling through the vacuum of free space, far away from the source, at the speed of light. As such, because this is a wave travelling at the speed of light, it is frame-independent in the sense that any spatial and temporal co-ordinates are defined by the observer as for e.x. light/EM waves and that the gravitons don't experience 'time' any more than photons do.

While the equations would be considerably more complicated, this could be extended to non-vacuum regions of space, although due to gravitational waves behaving so similarly to EM waves, I see no reason that the above idea of the observer defining the co-ordinate system wouldn't hold as above.

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.

0 comment threads

Sign up to answer this question »