Maxwell's first law in differential form states that $$ \triangledown \cdot E = \frac{\rho}{\epsilon_{o}} $$ . In case of 1d can we say that $$\rho = \lambda$$
where $$\lambda$$ is the linear char...

#1: Initial revision
by
MissMulan
·
2022-08-24T22:35:08Z (about 2 years ago)

maxwell equation in 1d

Maxwell's first law in differential form states that $$ \triangledown \cdot E = \frac{\rho}{\epsilon_{o}} $$ . In case of 1d can we say that $$\rho = \lambda$$
where $$\lambda$$ is the linear charge density of something?