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If we have a LC high pass filter the transfer function H(s) becomes: $$ H(s) = \cfrac{sL}{sL + \cfrac{1}{sC}} $$ If we solve for s to find a pole of the transfer function we get: $$ s = j \cfrac...
#3: Question closed
by
MissMulan
·
2022-07-10T18:43:25Z (over 2 years ago)
#2: Post edited
by
Canina
·
2022-07-10T18:43:08Z (over 2 years ago)
typeset formulae as formulae, not images
Meaning of complex frequency
- If we have a LC high pass filter the transfer function H(s) becomes:
- If we solve for s to find a pole of the transfer function we get:
In the case of a sinusoidal input signal = s = jω -> ω = 1/sqrt(LC)But in a case of a signal which may not be sinusoidal s can be a complex number and the result of this is that the pole exists at a complex frequency.But what physical meaning does a complex frequency have?
- If we have a LC high pass filter the transfer function H(s) becomes:
- $$ H(s) = \cfrac{sL}{sL + \cfrac{1}{sC}} $$
- If we solve for s to find a pole of the transfer function we get:
- $$ s = j \cfrac{1}{\sqrt{LC}} $$
- In the case of a sinusoidal input signal = $ s = j \omega \rightarrow \omega = \cfrac{1}{\sqrt{LC}} $
- But in a case of a signal which may not be sinusoidal s can be a complex number and the result of this is that the pole exists at a complex frequency. But what physical meaning does a complex frequency have?
#1: Initial revision
by
MissMulan
·
2022-07-08T18:15:32Z (over 2 years ago)
Meaning of complex frequency
If we have a LC high pass filter the transfer function H(s) becomes:  If we solve for s to find a pole of the transfer function we get:  In the case of a sinusoidal input signal = s = jω -> ω = 1/sqrt(LC) But in a case of a signal which may not be sinusoidal s can be a complex number and the result of this is that the pole exists at a complex frequency.But what physical meaning does a complex frequency have?