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The method is correct.
>when you write $s=vt$, $s$ is the horizontal distance and $v$ is the horizontal component of the initial velocity (and it happens to be that the initial velocity has only horizontal component but it could have been different), which does not change through the motion, that's why we can write  after all, this equation is when the velocity is constant (or when the velocity is the average velocity but this is not the case here). ~ [PF](https://www.physicsforums.com/threads/find-initial-velocity-when-a-stuntman-jumps-a-motorcycle-starting-from-a-1-25m-height.1006143/post-6529947)