Post History
A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$) I had solved it following way. $$h=\fra...
#2: Post edited
- >
- >A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)
- I had solved it following way.
- $$h=\frac{1}{2}gt^2$$
- $$=>1.25=5\cdot t^2$$
$$=>t=\frac{1}{2}$$- And, $$s=vt$$
- $$v=\frac{s}{t}$$
$$=\frac{10}{\frac{1}{2}}$$$$=20$$- The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.
- $$s=vt$$
- But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.
- >
- >A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)
- I had solved it following way.
- $$h=\frac{1}{2}gt^2$$
- $$=>1.25=5\cdot t^2$$
- $$=>t=\frac{1}{2} \ s$$
- And, $$s=vt$$
- $$v=\frac{s}{t}$$
- $$=\frac{10 \ m}{\frac{1}{2} \ s}$$
- $$=20 \ ms^{-1}$$
- The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.
- $$s=vt$$
- But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.
#1: Initial revision
Find initial velocity when a stuntman jump from $1.25 \ m$ height
>
>A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)
I had solved it following way.
$$h=\frac{1}{2}gt^2$$
$$=>1.25=5\cdot t^2$$
$$=>t=\frac{1}{2}$$
And, $$s=vt$$
$$v=\frac{s}{t}$$
$$=\frac{10}{\frac{1}{2}}$$
$$=20$$
The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.
$$s=vt$$
But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.