# Post History

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**#2: Post edited**

- >![figure](https://physics.codidact.com/uploads/Qx6oQqFzVdojVDba8YxSUjXH)
- >A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)
- I had solved it following way.
- $$h=\frac{1}{2}gt^2$$
- $$=>1.25=5\cdot t^2$$
~~$$=>t=\frac{1}{2}$$~~- And, $$s=vt$$
- $$v=\frac{s}{t}$$
~~$$=\frac{10}{\frac{1}{2}}$$~~~~$$=20$$~~- The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.
- $$s=vt$$
- But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.

- >![figure](https://physics.codidact.com/uploads/Qx6oQqFzVdojVDba8YxSUjXH)
- >A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)
- I had solved it following way.
- $$h=\frac{1}{2}gt^2$$
- $$=>1.25=5\cdot t^2$$
- $$=>t=\frac{1}{2}
**\ s**$$ - And, $$s=vt$$
- $$v=\frac{s}{t}$$
- $$=\frac{10
**\ m**}{\frac{1}{2}**\ s**}$$ - $$=20
**\ ms^{-1}**$$ - The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.
- $$s=vt$$
- But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.

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**#1: Initial revision**

Find initial velocity when a stuntman jump from $1.25 \ m$ height