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#2: Post edited by user avatar Anonymous‭ · 2021-08-17T09:13:30Z (5 months ago)
  • >![figure](https://physics.codidact.com/uploads/Qx6oQqFzVdojVDba8YxSUjXH)
  • >A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)
  • I had solved it following way.
  • $$h=\frac{1}{2}gt^2$$
  • $$=>1.25=5\cdot t^2$$
  • $$=>t=\frac{1}{2}$$
  • And, $$s=vt$$
  • $$v=\frac{s}{t}$$
  • $$=\frac{10}{\frac{1}{2}}$$
  • $$=20$$
  • The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.
  • $$s=vt$$
  • But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.
  • >![figure](https://physics.codidact.com/uploads/Qx6oQqFzVdojVDba8YxSUjXH)
  • >A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)
  • I had solved it following way.
  • $$h=\frac{1}{2}gt^2$$
  • $$=>1.25=5\cdot t^2$$
  • $$=>t=\frac{1}{2} \ s$$
  • And, $$s=vt$$
  • $$v=\frac{s}{t}$$
  • $$=\frac{10 \ m}{\frac{1}{2} \ s}$$
  • $$=20 \ ms^{-1}$$
  • The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.
  • $$s=vt$$
  • But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.
#1: Initial revision by user avatar Anonymous‭ · 2021-08-14T15:41:46Z (5 months ago)
Find initial velocity when a stuntman jump from $1.25 \ m$ height
>![figure](https://physics.codidact.com/uploads/Qx6oQqFzVdojVDba8YxSUjXH)
>A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)

I had solved it following way.

$$h=\frac{1}{2}gt^2$$
$$=>1.25=5\cdot t^2$$
$$=>t=\frac{1}{2}$$
And, $$s=vt$$
$$v=\frac{s}{t}$$
$$=\frac{10}{\frac{1}{2}}$$
$$=20$$

The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.

$$s=vt$$

But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.