Q&A

# Post History

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posted 1y ago by MissMulan‭  ·  edited 1y ago by deleted user

#2: Post edited by deleted user · 2021-08-14T13:00:32Z (about 1 year ago)
The phrase (your moving at a constant speed) isn’t looking good to me
• > But, when we are walking, running. We are accelerating.
• Wrong.When you are walking your moving at a costant speed.
• > The third law says we will never find a particle accelerating unless there’s some other particle accelerating somewhere else
• The book says that because of Netwon's 3rd law which says that forces only come in pairs , for each action there is a reaction.
• If two marbles collide then during the contact a force will be exerted on each marble , the one being the reaction of the second force.But those account as internal forces so the total change in momentum of the system is 0.
• Hope this helps.
• > But, when we are walking, running. We are accelerating.
• Wrong.When you are walking you're moving at a costant speed.
• > The third law says we will never find a particle accelerating unless there’s some other particle accelerating somewhere else
• The book says that because of Netwon's 3rd law which says that forces only come in pairs , for each action there is a reaction.
• If two marbles collide then during the contact a force will be exerted on each marble , the one being the reaction of the second force.But those account as internal forces so the total change in momentum of the system is 0.
• Hope this helps.
#1: Initial revision by MissMulan‭ · 2021-08-14T11:06:57Z (about 1 year ago)
 > But, when we are walking, running. We are accelerating.

Wrong.When you are walking your moving at a costant speed.

> The third law says we will never find a particle accelerating unless there’s some other particle accelerating somewhere else

The book says that because of Netwon's 3rd law which says that forces only come in pairs , for each action there is a reaction.

If two marbles collide then during the contact a force will be exerted on each marble , the one being the reaction of the second force.But those account as internal forces so the total change in momentum of the system is 0.

Hope this helps.