# Post History

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**#3: Post edited**

- I was reading "Introduction to classical Mechanics" by David Morin. In that book they wrote that
~~>The third law says we will never find a particle accelerating unless there’s some other particle accelerating somewhere else. The other particle might be far away, as with the earth–sun system.~~- But, when we are walking, running. We are accelerating. Even, vehicles are accelerating also. But, why the definition says,"we can't find a particle accelerating ......." Seems like they talking about QM (I am not sure) cause, in "Classical" World I can see everything accelerating but, they had talked about particle which means they are referring to Quantum World. It's looking like Quantum Entanglement cause, when a particle (big object) is far away than, they can't contact in Classical World but, if we think of QM than, they can contact (That's why I am referring to QM).
- $$\frac{d_{Ptotal}}{dt} = \frac{dp_1}{dt} + \frac{dp_2}{dt}$$
- They wrote the above equation. Then talked about above definition. What I understood from the equation that is,"We can't find a particle accelerating cause, a particle always (not in Quantum World) has equal of negative force so, until two particles contact each other their momentum is forever $0$"

- I was reading "Introduction to classical Mechanics" by David Morin. In that book they wrote that
- >The third law says we will never find a particle accelerating unless there’s some other particle accelerating somewhere else. The other particle might be far away, as with the earth–sun system
**, but it’s always out there somewhere**. - But, when we are walking, running. We are accelerating. Even, vehicles are accelerating also. But, why the definition says,"we can't find a particle accelerating ......." Seems like they talking about QM (I am not sure) cause, in "Classical" World I can see everything accelerating but, they had talked about particle which means they are referring to Quantum World. It's looking like Quantum Entanglement cause, when a particle (big object) is far away than, they can't contact in Classical World but, if we think of QM than, they can contact (That's why I am referring to QM).
- $$\frac{d_{Ptotal}}{dt} = \frac{dp_1}{dt} + \frac{dp_2}{dt}$$
- They wrote the above equation. Then talked about above definition. What I understood from the equation that is,"We can't find a particle accelerating cause, a particle always (not in Quantum World) has equal of negative force so, until two particles contact each other their momentum is forever $0$"

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**#2: Post edited**

- I was reading "Introduction to classical Mechanics" by David Morin. In that book they wrote that
~~>The third law says we will never find a particle accelerating unless there’s some other particle accelerating somewhere else.~~- But, when we are walking, running. We are accelerating. Even, vehicles are accelerating also. But, why the definition says,"we can't find a particle accelerating ......." Seems like they talking about QM (I am not sure) cause, in "Classical" World I can see everything accelerating but, they had talked about particle which means they are referring to Quantum World. It's looking like Quantum Entanglement cause, when a particle (big object) is far away than, they can't contact in Classical World but, if we think of QM than, they can contact (That's why I am referring to QM).
- $$\frac{d_{Ptotal}}{dt} = \frac{dp_1}{dt} + \frac{dp_2}{dt}$$
- They wrote the above equation. Then talked about above definition. What I understood from the equation that is,"We can't find a particle accelerating cause, a particle always (not in Quantum World) has equal of negative force so, until two particles contact each other their momentum is forever $0$"

- I was reading "Introduction to classical Mechanics" by David Morin. In that book they wrote that
- >The third law says we will never find a particle accelerating unless there’s some other particle accelerating somewhere else.
**The other particle might be far away, as with the earth–sun system.** - $$\frac{d_{Ptotal}}{dt} = \frac{dp_1}{dt} + \frac{dp_2}{dt}$$