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This suggested edit was rejected over 2 years ago by deleted user:

writing Math using MathJax is better choice

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  • Find initial velocity when a stuntman jump from $1.25 \ m$ height
  • Find initial velocity when a stuntman jump from 1.25 m height
>![figure](https://physics.codidact.com/uploads/Qx6oQqFzVdojVDba8YxSUjXH)
>A stuntman jumped from $1.25 \ \text{m}$ height and, landed at distance $10 \ \text{m}$. Find velocity when he jumped. (Take $\text{g}=10 \ ms^{-2}$)

I had solved it following way.

$$h=\frac{1}{2}gt^2$$
$$=>1.25=5\cdot t^2$$
$$=>t=\frac{1}{2} \ s$$
And, $$s=vt$$
$$v=\frac{s}{t}$$
$$=\frac{10 \ m}{\frac{1}{2} \ s}$$
$$=20 \ ms^{-1}$$

The answer is correct (checked from book answer). But, $v$ is average speed in the following equation.

$$s=vt$$

But, they told me to find initial velocity. That's why I think my answer is correct but, method is wrong so, the whole work is wrong either.

Suggested over 2 years ago by Canina‭